Aim:- To analyse the acidic and basic
radicals in the given salt.
Physical appearance:-
Colour: White
Smell: Odourless
Appearance: Amorphous
Dry heating test:-
Procedure
|
Observation
|
Inference
|
Take a small amount of the salt in a dry
test tube and heat.
|
Brown when hot and yellow when cold.
|
Pb2+ may be present.
|
Flame test:-
Procedure
|
Observation
|
Inference
|
Prepare a paste of the salt with
concentrated HCL on a clean watch glass. Place small amount of this paste on platinum
wire loop and introduce it into the flame.
|
Colour of the flame turns dull bluish
white.
|
Pb2+ may be present.
|
Concentrated sulfuric acid test:-
Procedure
|
Observation
|
Inference
|
Take a small amount of the salt in a test
tube and add 1-2 ml of concentrated sulphuric acid.
|
No gas / vapours evolved
|
CH3COO- may be
present.
|
Confirmation of acid radicals by wet test:-
Aqueous solution or water extract: Shake a
little amount of the salt with water. If the salt dissolves, this aqueous
solution obtained is used for the wet tests of acid radicals and is called
water extract or 'W.E'.
Procedure
|
Observation
|
Inference
|
(i) Oxalic acid
test:- Take a small quantity of the salt on a watch glass. Mix it with solid
oxalic acid. Prepare paste of it with a few drops of water. Rub the paste and
smell.
|
Smell like that
of vinegar.
|
CH3COO-
may be present.
|
(ii) Ester test:- take a small quantity
of the salt in the test tube. Add concentrated H2SO4 (0.2
ml) and heat. Now add ethyl alcohol (1 ml). Shake and pour the contents of
the tube in a beaker full of water and stir.
|
Pleasant fruity
smell of ester.
|
CH3COO-
is present.
|
Wet test for
basic radicals (cations):-
Preparation of
original solution: Take a small
quantity of the given salt in a test tube and add some distilled water do it
and shake the contents. If the salt does not dissolve, heat the content till
the salt completely dissolves. The clean solution thus obtained is labelled as
original solution (O.S).
Procedure
|
Observation
|
Inference
|
(i) Add dilute
HCL to the original solution.
|
White
precipitate is formed.
|
Pb2+
may be present.
|
(ii) Potassium
iodide test:- to the one part add KI solution.
|
Yellow
precipitate is formed.
|
Pb2+
is present.
|
(iii) Potassium
chromate test:- To the other part add K2CrO4 solution.
|
Yellow
precipitate is formed.
|
Pb2+
is present.
|
Result:-
Acid Radical: CH3COO-
Basic Radical: Pb2+
Therefore, The
salt is Pb(CH3COO)2.
Good
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